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Queuing models use an A/B/C notation. What do these variables represent? A. maximum time between arrivals/maximum allowable service time/maximum number of parallel servers B. average time between
arrivals/average service time/number of parallel servers C. minimum time between arrivals/minimum allowable service time/minimum number of parallel servers D. distribution of time between arrivals/distribution of service times/number of parallel servers
The distribution of time between arrivals/distribution of service times/number of parallel servers.
Expert answered|jeifunk|Points 7730|
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Asked 11/8/2012 10:58:57 AM
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Sampling error can be reduced by __________. A. utilizing simple random samples B. decreasing the sample size C. none of the these affect sampling error D. increasing the sample size
Weegy: Sampling error can be reduced by increasing the sample size. User: In a random sample of 810 women employees, it is found that 81 would prefer working for a female boss. The width of the 95% confidence interval for the proportion of women who prefer a female boss is _____. A. ± .0105 B. ± .0196 C. ± .0288 D. ± .0207 Weegy: B. ??? .0288 User: Which of the following statements is true? A. The sum of two mutually exclusive events is one. B. The probability of A and its complement (A') will always sum to one. C. If A and B are independent events, the P(B) = P(A) P(B). D. If event (A) occurs, then its complement (A') will also occur. Weegy: B. The probability of A and its complement (A') will always sum to one is the true statement User: ) Independent events A and B would be consistent with which of the following statements: A. P (A) = .4, P (B) = .3, P (A B) = .5 B. P (A) = .3, P (B) = .5, P (A B) = .4 C. P (A) = .5, P (B) = .4, P (A B) = .3 D. P (A) = .4, P (B) = .5, P (A B) = .2 Weegy: The answer is D. [ P (A) = .4, P (B) = .5, P (A B) = .2. Multiplication Rule for Independent events A and B : When two events, A and B, are independent, the probability of both occurring is: P(A and B) = P(A) · P(B) ] (More)
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Asked 11/8/2012 10:53:33 AM
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