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Q: Divide: 6x3 + 27x - 19x2 - 15 by 3x -5
A: (6x^3 + 27x - 19x^2 - 15) /(3x -5) = (6x^3/3x - 5) + (27x/3x - 5) + (-19x^2/3x - 5) + (-15/3x - 5) = 2x^2 - 3x + 4 R. 5
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Asked 12/8/2011 3:11:56 PM
Updated 160 days ago|1/8/2018 5:58:10 PM
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(6x^3 + 27x - 19x^2 - 15) /(3x -5)
= (6x^3/3x - 5) + (27x/3x - 5) + (-19x^2/3x - 5) + (-15/3x - 5)
= 2x^2 - 3x + 4 R. 5
Added 160 days ago|1/8/2018 5:58:10 PM
This answer has been confirmed as correct and helpful.
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