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Q: Standard form of equation of a circle with end points of a diameter at the points (1,2),(-5,4)
A: Standard form of equation of a circle with end points of a diameter at the points (1, 2),(-5, 4) is (x + 2)^2 + (y - 3)^2 = 10.
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User: Standard form of equation of a circle with end points of a diameter at the points (1,2),(-5,4)

Weegy: step 1: x = -5+(5+3) step 2: x = -5 + 8 step 3: x = 8-5 step 4: x = 3
Expert answered|SarahS.|Points 7|

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Asked 6/3/2011 3:18:57 PM
Updated 7/22/2014 1:08:11 AM
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This conversation has been flagged as incorrect.
Flagged by yeswey [7/22/2014 1:07:08 AM]
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Standard form of equation of a circle with end points of a diameter at the points (1, 2),(-5, 4) is (x + 2)^2 + (y - 3)^2 = 10.
Added 7/22/2014 1:08:11 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [7/22/2014 1:15:50 AM]
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