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Find the cube root of 64.
2
4
8
32 **Weegy:** cube root of 64 = 4
4 x 4 = 16, and 16 x 4 = 64
4 cube = 64
**User:** what is the cube root of 64? **Weegy:** The cube root of 64 is 4. (More)

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Asked 6/6/2013 6:34:05 AM

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If Susie is 14, what was her age x years ago?
x- 14
14 -x
14x

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Updated 218 days ago|9/26/2014 10:59:05 PM

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Choose the equation that best represents the general form of the following expression.
x^2/2=7x **Weegy:** 7x = 14 ; x = 14/7 ; x = 2 (More)

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Expert Answered

Asked 6/7/2013 6:32:30 AM

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What is the solution set of the following equation?
(2x - 5)(3x + 1) = 0 **Weegy:** x = 27/4 **User:** Choose the equation that models the following problem.
When the side of a square is doubled, its area is increased to 28 cm2.
2x= 28
2x2= 28
(2x)2= 28
2x=x2+ 28 **Weegy:** The sides of the square are both 8cm(its a square, and 8 squared is 64)
So the diameter of the circle is 8cm, and the radius is 4.
The area = pi(4^2) = 16pi. **User:** Determine the solution set of (x + 2)2 = 36. (More)

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Updated 303 days ago|7/4/2014 1:56:57 AM

3 Answers/Comments

(2x - 5)(3x + 1) = 0

2x - 5 = 0 or 3x + 1 = 0

x = 5/2 or x = -1/3

The solution set for the equation (2x - 5)(3x + 1) = 0 is {5/2, -1/3)

2x - 5 = 0 or 3x + 1 = 0

x = 5/2 or x = -1/3

The solution set for the equation (2x - 5)(3x + 1) = 0 is {5/2, -1/3)

Added 303 days ago|7/4/2014 1:54:33 AM

This answer has been confirmed as correct, not copied, and helpful.

Confirmed by yumdrea [7/4/2014 3:02:02 PM]

When the side of a square is doubled, its area is increased to 28 cm^2. The equation for the problem is (2x)^2= 28 where x is the side of the square.

Added 303 days ago|7/4/2014 1:55:52 AM

This answer has been confirmed as correct, not copied, and helpful.

Confirmed by yumdrea [7/4/2014 3:02:04 PM]

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