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Find the cube root of 64. 2 4 8 32
Weegy: cube root of 64 = 4 4 x 4 = 16, and 16 x 4 = 64 4 cube = 64 User: what is the cube root of 64? Weegy: The cube root of 64 is 4. (More)
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Asked 6/6/2013 6:34:05 AM
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If Susie is 14, what was her age x years ago? x- 14 14 -x 14x
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Updated 243 days ago|9/26/2014 10:59:05 PM
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If Susie is 14, her age x years ago is 14 - x .
Added 243 days ago|9/26/2014 10:59:05 PM
105/3=?
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Not Answered
Updated 29 days ago|4/28/2015 1:10:40 PM
1 Answer/Comment
105/3=35
Added 29 days ago|4/28/2015 1:10:40 PM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by jeifunk [4/28/2015 1:11:37 PM]
Choose the equation that best represents the general form of the following expression. x^2/2=7x
Weegy: 7x = 14 ; x = 14/7 ; x = 2 (More)
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Asked 6/7/2013 6:32:30 AM
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What is the solution set of the following equation? (2x - 5)(3x + 1) = 0
Weegy: x = 27/4 User: Choose the equation that models the following problem. When the side of a square is doubled, its area is increased to 28 cm2. 2x= 28 2x2= 28 (2x)2= 28 2x=x2+ 28 Weegy: The sides of the square are both 8cm(its a square, and 8 squared is 64) So the diameter of the circle is 8cm, and the radius is 4. The area = pi(4^2) = 16pi. User: Determine the solution set of (x + 2)2 = 36. (More)
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Updated 327 days ago|7/4/2014 1:56:57 AM
3 Answers/Comments
(2x - 5)(3x + 1) = 0
2x - 5 = 0 or 3x + 1 = 0
x = 5/2 or x = -1/3
The solution set for the equation (2x - 5)(3x + 1) = 0 is {5/2, -1/3)
Added 327 days ago|7/4/2014 1:54:33 AM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by yumdrea [7/4/2014 3:02:02 PM]
When the side of a square is doubled, its area is increased to 28 cm^2. The equation for the problem is (2x)^2= 28 where x is the side of the square.
Added 327 days ago|7/4/2014 1:55:52 AM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by yumdrea [7/4/2014 3:02:04 PM]
(x + 2)^2 = 36
x + 2 = 6 or x + 2 = -6
x = 4 or x = -8
The solution set for the equation (x + 2)^2 = 36 is {4, -8}
Added 327 days ago|7/4/2014 1:56:57 AM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by yumdrea [7/4/2014 3:02:03 PM]
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