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Q: Find the center and radius of the circle with the given equation: x^2 + y^2 + 6y = -50 - 14x
A: x^2 + y^2 + 6y = -50 - 14x x^2 + 14x + y^2 + 6y = -50 x^2 + 14x + 49 + y^2 + 6y + 9 = -50 + 49 + 9 (x + 7)^2 + (y + 3)^2 = 8 we can tell the center for the circle is (-7, -3) and the radius is 2 sqrt 2
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User: Find the center and radius of the circle with the given equation: x^2 + y^2 + 6y = -50 - 14x





Weegy: Mathematically speaking, the answer would be x~~-9.82843, y~~-3.. Source: Wolfram|Alpha
Expert answered|ailahlin|Points 120|

Question
Asked 6/29/2012 1:28:44 PM
Updated 7/13/2014 8:07:41 PM
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This conversation has been flagged as incorrect.
Flagged by yeswey [7/13/2014 8:07:34 PM]
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x^2 + y^2 + 6y = -50 - 14x
x^2 + 14x + y^2 + 6y = -50
x^2 + 14x + 49 + y^2 + 6y + 9 = -50 + 49 + 9
(x + 7)^2 + (y + 3)^2 = 8
we can tell the center for the circle is (-7, -3) and the radius is 2 sqrt 2
Added 7/13/2014 8:07:41 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [7/16/2014 10:53:29 AM]
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