You have new items in your feed. Click to view.
Q: Find the center and radius of the circle with the given equation: x^2 + y^2 + 6y = -50 - 14x
A: x^2 + y^2 + 6y = -50 - 14x x^2 + 14x + y^2 + 6y = -50 x^2 + 14x + 49 + y^2 + 6y + 9 = -50 + 49 + 9 (x + 7)^2 + (y + 3)^2 = 8 we can tell the center for the circle is (-7, -3) and the radius is 2 sqrt 2
Original conversation
User: Find the center and radius of the circle with the given equation: x^2 + y^2 + 6y = -50 - 14x

Weegy: Mathematically speaking, the answer would be x~~-9.82843, y~~-3.. Source: Wolfram|Alpha

Question
Updated 7/13/2014 8:07:41 PM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/13/2014 8:07:34 PM]
Rating
3
x^2 + y^2 + 6y = -50 - 14x
x^2 + 14x + y^2 + 6y = -50
x^2 + 14x + 49 + y^2 + 6y + 9 = -50 + 49 + 9
(x + 7)^2 + (y + 3)^2 = 8
we can tell the center for the circle is (-7, -3) and the radius is 2 sqrt 2
Confirmed by andrewpallarca [7/16/2014 10:53:29 AM]

*
Get answers from Weegy and a team of really smart lives experts.
S
L
Points 247 [Total 265] Ratings 0 Comments 177 Invitations 7 Offline
S
L
Points 130 [Total 130] Ratings 0 Comments 130 Invitations 0 Offline
S
L
R
Points 125 [Total 276] Ratings 1 Comments 5 Invitations 11 Offline
S
R
L
R
P
R
P
R
Points 66 [Total 734] Ratings 0 Comments 6 Invitations 6 Offline
S
1
L
L
P
R
P
L
P
P
R
P
R
P
R
P
P
Points 62 [Total 13329] Ratings 0 Comments 62 Invitations 0 Offline
S
L
1
R
Points 34 [Total 1450] Ratings 2 Comments 14 Invitations 0 Offline
S
L
Points 10 [Total 187] Ratings 0 Comments 0 Invitations 1 Offline
S
Points 10 [Total 13] Ratings 0 Comments 10 Invitations 0 Offline
S
Points 10 [Total 10] Ratings 0 Comments 0 Invitations 1 Offline
S
Points 2 [Total 2] Ratings 0 Comments 2 Invitations 0 Offline
* Excludes moderators and previous
winners (Include)
Home | Contact | Blog | About | Terms | Privacy | © Purple Inc.