how do you change the subject in maths

Is there something specific you want to know about Maths?

tezyah|Points 1226|

Expert answered|lotus16|Points 1|

Expert answered|lotus16|Points 1|

Question

Asked 4/29/2009 10:10:38 AM

0 Answers/Comments

Rating

There are no new answers.

how do you work out 4x-2=2x+10 **Weegy:** First move the things that have x in them to one side, say the left side, and then move the numbers that are by themselves to the otherside. So you should have 4x-2x=10+2. Simplifying would bring you 2x=12. [ Then divide out the 2 from both sides so we get x alone. x=6. ] (More)

Question

Expert Answered

Asked 4/29/2009 9:41:45 AM

0 Answers/Comments

how do you work out v=u+at **Weegy:** what is the initial equation for this problem? (More)

Question

Expert Answered

Asked 4/29/2009 10:00:10 AM

0 Answers/Comments

how do you work out c=4a+2b **Weegy:** what is the initial question for this problem? **User:** i dont know how do you change the subject? **Weegy:** one moment please... (More)

Question

Expert Answered

Updated 4/29/2009 11:52:23 AM

1 Answer/Comment

to be able to solve this problem you first need to find or look up the values for A and B - for example if A is 5 and B is 10 you would solve it like this

C=4 (5) + 2(10)

C= 20 + 20

C+ 40

I hope this help

C=4 (5) + 2(10)

C= 20 + 20

C+ 40

I hope this help

Added 4/29/2009 11:52:23 AM

how change the subject in a formula? **Weegy:** what is the formula that you are trying to change the subject to? **User:** x=y-2z **Weegy:** ok i have an example for you maybe this will help...0.5zx + 0.5zy + 0.5yx + 0.5yz
0.5zx + 0.5 yx + yz
0.5x(y+z) + yz
W - yz = 0.5x(y+z)
then divide by 0.5(y+z) [or multiply by 2/(y+z)]
should get
2(W-yz) over (y+z) **User:** no sorry to complicated **Weegy:** 0.5zx + 0.5zy + 0.5yx +0.5yz
0.5zx + 0.5 yx + yz
0.5x(y+z) + yz
[
W - yz = 0.5x(y+z)
then divide by 0.5(y+z) [or multiply by 2/(y+z)]
should get
2(W-yz) over (y+z) ] (More)

Question

Expert Answered

Asked 4/29/2009 10:14:00 AM

0 Answers/Comments

17,956,502 questions answered

There are no comments.