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Q: (6f2 - 13 - 11f) (3f - 4)
A: (6f^2 - 13 - 11f) (3f - 4) = 18f^3 - 24f^2 - 39f + 52 - 33f^2 + 44f; = 18f^3 - 57f^2 + 5f + 52
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Asked 9/19/2012 9:01:51 AM
Updated 12/27/2014 3:39:22 AM
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(6f^2 - 13 - 11f) (3f - 4)

= 18f^3 - 24f^2 - 39f + 52 - 33f^2 + 44f;

= 18f^3 - 57f^2 + 5f + 52
Added 12/27/2014 3:39:22 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [12/27/2014 5:18:54 AM]
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