Weegy: Solve c2 6c- 27 = 0 by completing the square
Answer:
(c+9)(c-3) therefore c= -9 and 3.
Completing the square...
(c+3)*(c+3)=c^2+6*c+9
..that's got the c^2 and c terms right.
Just add a constant on the end to get -27 rather than [ 9
(c+3)^2 - [ 36=0
(c+3)^2=36
c+3= +/- 6
c=3, c=-9
] ] (More)

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