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Q: Evaluate the polynomial. -2x^2 - y^2 + xy, when x = -3 and y = 5
A: This conversation has been flagged as incorrect. New answers have been added below ....
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Original conversation
User: -2x^2-y^2+xy x=-3 y=5

User: Evaluate the polynomial. -2x^2 - y^2 + xy, when x = -3 and y = 5

Weegy: (-2x - 6)2= -2(x + 3)2= -2y. So, (-2x - 6)2 must equal -2y
shifa saleheen|Points 8864|

User: simply (-4a^2)^5

Weegy: please clear the question
rio8408|Points 400|

User: Simplify (-4a^2)^5

Question
Asked 1/22/2012 3:45:16 PM
Updated 6/13/2014 1:52:50 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [6/13/2014 1:51:22 PM]
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3
-2x^2 - y^2 + xy, x = -3, y = 5:

-2(-3)^2 - (5)^2 + (-3)(5)

= -2(9) - 25 - 15

= -18 - 25 - 15

= -18 - 40

= -58
Added 6/13/2014 1:51:18 PM
This answer has been confirmed as correct and helpful.
3
(-4a^2)^5 = -1,024a^10;

Added 6/13/2014 1:52:50 PM
This answer has been confirmed as correct and helpful.
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