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Q: What is the equation of y = x3 with the given transformations? vertical stretch by a factor of 3, horizontal shift 4 units to the right, vertical shift 3 units down
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What is a quartic function with only the two real zeroes given? x=5, x=1
Weegy: x = -4 User: Find a quadratic equation with roots –1 + 4i and –1 – 4i. User: 10. Find all the zeroes of the equation.–3x4+ 27x2 + 1200 = 0 Weegy: The answer is -12+54+1200=0. (More)
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Updated 12/9/2014 12:19:36 AM
The quadratic function with only the two real zeroes x=5, x=1 is x^2 - 6x + 5 = 0.
Deleted by yeswey [12/9/2014 12:16:27 AM], Undeleted by yeswey [12/9/2014 12:16:37 AM]
All the zeroes of the equation –3x^4+ 27x^2 + 1200 = 0 is:
x1 = 5, x2 = -5, x3 = -4i, x4 = 4i
Confirmed by jeifunk [12/9/2014 12:49:15 AM]
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