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6.28 as a fraction
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Expert answered|geofox888|Points 56|
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Asked 6/24/2012 2:59:25 PM
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Given that f(x) = x² + 5x, evaluate f(-2)? -6 -14 7
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Not Answered
Updated 61 days ago|3/1/2016 4:08:31 AM
1 Answer/Comment
f(x) = x² + 5x, evaluate f(-2),
f(-2) = (-2)^2 + 5(-2)
f(-2) = 4 - 10
f(-2) = - 6
Added 61 days ago|3/1/2016 4:08:31 AM
This answer has been confirmed as correct, not copied, and helpful.
Evaluate 3|-4| 12 4 -12
Weegy: there is no solution set for that. Please write the whole question User: Evaluate 3|-4| 12 4 -12 Weegy: there is no solution set for that. Please write the whole question User: The solution set of |R - 3| = 10 is {7, 13} {-7, 13} {-13, 13} Weegy: The answers are {7,13} (More)
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Expert Answered
Updated 9/22/2014 12:51:56 PM
2 Answers/Comments
3|-4| = 3(4) = 12
Added 9/22/2014 12:50:42 PM
This answer has been confirmed as correct, not copied, and helpful.
The solution set of |R - 3| = 10 is {-7, 13}.

|R - 3| = 10;
R - 3 = 10;
R = 10 + 3;
R = 13;
-(R - 3) = 10;
-R + 3 = 10;
-R = 10 - 3;
-R = 7; R = -7
Added 9/22/2014 12:51:53 PM
This answer has been confirmed as correct, not copied, and helpful.
Evaluate |-7| + 3|4| 0 5 19
Weegy: |-7| + 3|4| = 7 + 3(4) = 7 + 12 = 19 User: Evaluate 2|-1| Weegy: 2|-1|= 2(1) = 2 User: Evaluate -|-8 - 2| Weegy: -|-8 - 2| = -10 User: The solution set of |a| = 4 is {-4} {4} {-4, 4} (More)
Question
Expert Answered
Updated 9/22/2014 12:54:29 PM
1 Answer/Comment
The solution set of |a| = 4 is {-4, 4}.
Added 9/22/2014 12:54:29 PM
This answer has been confirmed as correct, not copied, and helpful.
The solution set of the equation |x - 1| = 3 is {-2, 4} {-3, 3} {-4, 2}
Weegy: |x - 1|= 3; x - 1 = 3; x = 3 + 1; x = 4; -(x - 1) = 3; -x + 1 = 3; -x = 3 - 1; -x = 2; x = -2. The solution set of the equation |x - 1| = 3 is {-2, 4}. (More)
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Expert Answered
Updated 9/22/2014 12:56:50 PM
0 Answers/Comments
Simplify 24÷(-2)(3)+7 -29 3 11
Weegy: The answer is -26 (More)
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Expert Answered
Updated 9/22/2014 1:05:56 PM
1 Answer/Comment
24÷ (-2)(3) + 7
= (-12)(3) + 7
= -36 + 7
= -29
Added 9/22/2014 1:05:54 PM
This answer has been confirmed as correct, not copied, and helpful.
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