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Q: What is the solution set of 7x^2 + 3x = 0?
A: 7x^2 + 3x = 0; x(7x + 3) = 0; x = 0; 7x + 3 = 0; 7x = -3; x = -3/7; x = {0, -3/7}
Original conversation
User: What is the solution set of 7x^2 + 3x = 0?

Weegy: First you will want to take the 5 and multiply it to the -3X and 4 so it will look like this: 7X -15X-20=-21-7X Got it? Then you will combine the X's on the first side so you will get this: -8X-20= -21-7X Next you need to get the X's on [ [ [ one side so you will take the one that is less, in this case -8X and add it to the -7X. When it crosses over the equal mark it becomes a positive so you will get this next: -20=-21 + X <------you get 1X here but it is not necessary to put the 1 Next you want to get the X by itself so you will add the-21 (because it is the lowest) to the other side. Again, when you cross a negative to the other side it becomes a positive. So here is your final result: 1=X Hope that helped! ] ] ]

Question
Updated 8/17/2014 3:03:21 PM
This conversation has been flagged as incorrect.
Flagged by alfred123 [8/17/2014 3:03:12 PM]
Rating
3
7x^2 + 3x = 0;

x(7x + 3) = 0;

x = 0;

7x + 3 = 0;
7x = -3;
x = -3/7;

x = {0, -3/7}
Confirmed by andrewpallarca [8/17/2014 3:08:45 PM]

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