Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
3-inch radius
how much will this be A = sq. in.?

The area of an equilateral triangle, regular 3-gon, with the given measurement, 3-inch radius A=square inch is 9 inches squared.

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Asked 5/10/2012 4:35:35 PM

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When chords intersect in a circle, the vertical angles formed intercept congruent arcs.?

Weegy: That is called "Chord Central Angles Conjecture." (More)

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Asked 5/4/2012 12:02:21 PM

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can you please help me Find the area of an equilateral triangle (regular 3-gon) with the given measurement.?
6-inch side.
A = sq. in.?

Weegy: Here are the shortcut formulas, perimeter is P=3s, area is A=(1/2)sh, h=[(sqrt 3)/2]s where h is height and s is side, all sides are equal, if the given is radius it means it is in the center, so from any point to center is equal length. r=(2/3)h. [ I also have my own equation if r is given to get the side instantly, s^2=(2x)^2-x^2 where x is radius. i'll answer #1 to give idea. So given r=3in, apply s^2=(2x)^2-x^2, so s^2=(2*3)^2-3^2 => ... (More)

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Asked 5/7/2012 1:19:07 AM

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can you please help me Find the area of an equilateral triangle (regular 3-gon) with the given measurement.?
6-inch radius
A = sq. in.?

Weegy: Can you kindly complete the details for your question please. User: what is for equilateral triangle (regular 3-gon) with the given measurement.
6-inch radius
A = sq. in.? (More)

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Asked 5/7/2012 1:24:21 AM

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9-inch perimeter how many will it be
A = sq. in.?

Weegy: what is the polygon's shape? (More)

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Asked 5/7/2012 2:47:14 AM

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(regular 3-gon)

Weegy: The regular 3-gon, known as the equilateral triangle, was constructed in I.1, while the regular 4-gon, known as the square, was constructed in I.46. In book IV, regular 5-gons and regular 6-gons have been constructed. [ An application of III.30 (which was used in this proposition) can double the number of sides of a regular polygon, and therefore regular polygons with 8, 10, 12, 16, 20, 24, etc., sides can be constructed. This ... (More)

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Asked 5/7/2012 2:49:09 AM

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