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Question and answer
Q: find x: 3(x-5)=0
A: 3(x-5)=0; 3x - 15 = 0, 3x = 15, x = 15/3, x = 5
Expert answered|shifa saleheen|Points 8114|
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Asked 12/4/2011 6:25:10 PM
Updated 8/17/2014 6:25:55 PM
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This answer has been confirmed as correct and helpful.
Edited by andrewpallarca [8/17/2014 6:25:53 PM], Confirmed by andrewpallarca [8/17/2014 6:25:55 PM]
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The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.
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