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Q: find x: 3(x-5)=0
A: 3(x-5)=0; 3x - 15 = 0, 3x = 15, x = 15/3, x = 5
Question
Updated 8/17/2014 6:25:55 PM
Edited by andrewpallarca [8/17/2014 6:25:53 PM], Confirmed by andrewpallarca [8/17/2014 6:25:55 PM]
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A ______________ is one in which the highest power of the unknown is two. Its general form is ax^2+bx+c=0
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Updated 8/17/2014 6:25:04 PM
A quadratic equation is one in which the highest power of the unknown is two. Its general form is ax^2+bx+c=0.
Confirmed by andrewpallarca [8/17/2014 6:25:05 PM]
Solve: (6x^2+5x-1) ÷ (2x+1)
Weegy: (6x^2+5x-1) ÷ (2x+1) =((x+1)(6x-1))/(2x+1) (More)
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Updated 12/5/2011 5:30:10 AM
The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.
Confirmed by andrewpallarca [8/17/2014 6:29:44 PM]
Solve: (6x^2+5x-1) ÷ (2x+1)
Weegy: Is it a quadratic equation? User: No please divide the polynomials Weegy: 6x^2 + 2.5x+1 User: Sorr I dont understand your answer? (More)
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Updated 12/5/2011 5:30:38 AM
The quotient of 6x^2 + 5x - 1 and 2x + 1 is 3x + 1 with a remainder of -2. To solve this. Divide 6x^2 and 2x. Multiply 3x and 2x + 1, you'll get 6x^2 + 3x. Subtract 6x^2 + 3x from 6x^2 + 5x, you'll get 2x, then bring down -1. Divide 2x - 1 and 2x + 1, you'll get 1 with a remainder of - 2. So the final result is 3x + 1 with a remainder of -2.
Confirmed by andrewpallarca [8/13/2014 6:31:03 PM]
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Updated 9/1/2014 5:16:40 AM
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