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Q: A man bought 42 stamps, some 13¢ and some 18¢. How many of each kind did he buy if the cost was $6.66?
A: Let the amount of 13? stamps purchased be x Let the amount of 18? stamps purchased be y x+y=42................................? 0.13x+0.18y=6.66.....................(? Rewrite (1), x=42-y................................? Substitute x in [ [ (2), 0.13(42-y)+0.18y=6.66 5.46-0.13y+0.18y=6.66 0.05y=1.2 y=24 x=18 Therefore, the man bought 18 13? stamps and 24 18? stamps. ] ]
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Original conversation
User: A man bought 42 stamps, some 13¢ and some 18¢. How many of each kind did he buy if the cost was $6.66?

Weegy: Let the amount of 13? stamps purchased be x Let the amount of 18? stamps purchased be y x+y=42................................? 0.13x+0.18y=6.66.....................(? Rewrite (1), x=42-y................................? Substitute x in [ [ (2), 0.13(42-y)+0.18y=6.66 5.46-0.13y+0.18y=6.66 0.05y=1.2 y=24 x=18 Therefore, the man bought 18 13? stamps and 24 18? stamps. ] ]
Controler|Points 3928|

User: man invests $5,200, part at 4% and the balance at 3%. If his total income for the two investments is $194, how much money did he invest at each rate?

Weegy: Interest = Investment * Rate X = amount invested at 4% $5,200 - X = amount invested at 3% 194 = 0.04X + 0.03(5,200 - X) 194 = 0.04X + 156 - 0.03X 38 = 0.01X X = 3800 Answer: $3,800 is invested at 4% and $1200 is invested at 3% Check: $3,800 * 4% = [ $152 $1,200 * 3% = $36 $152 + $36 = $192 ]
jher000|Points 8061|

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Asked 6/18/2013 9:30:00 AM
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