Question and answer
Explain how to factor the following trinomials forms: x2 + bx + c and ax2 + bx + c. Is there more than one way to factor this? Give an example for your classmates to factor.
Let's factor the trinomial x² + bx + c. We know that if b²-4c >= 0 then this trinomial has zeros and it can be factorized. [ It's zeros are x1 = [ -b + v(b²-4c) ] / 2 and x2 = [ -b - v(b²-4c) ] / 2. So, we can factor it as x² + bx + c = (x-x1)(x-x2). In a case of trinomial ax² + bx + c we can factorize it as ax² + bx + c = a(x² + b/a·x + c/a), where the trinomial x² +
b/a·x + c/a has the same form as x² + bx + c. For example, I will pick 2x + 5 and 6x - 1 as my two linear expressions Multiplying them together (2x + 5)(6x - 1) gives 12x^2 - 2x + 30x - 5 = 12x^2 + 28x - 5, which is a factorable polynomial of the form ax^2 + bx + c ]
Expert answered|emdjay23|Points 537|
Question
Asked 3/12/2013 3:10:24 PM
0 Answers/Comments
Get an answer
New answers
Rating

There are no new answers.

Comments

There are no comments.

Add an answer or comment
Log in or sign up first.
23,939,127 questions answered
Weegy Stuff
S
Points 357 [Total 754] Ratings 0 Comments 357 Invitations 0 Online
S
P
P
L
Points 240 [Total 1047] Ratings 0 Comments 240 Invitations 0 Offline
S
1
L
L
P
R
P
L
P
Points 125 [Total 11298] Ratings 0 Comments 125 Invitations 0 Offline
S
L
P
Points 84 [Total 2152] Ratings 0 Comments 84 Invitations 0 Offline
S
Points 4 [Total 904] Ratings 0 Comments 4 Invitations 0 Offline
S
Points 2 [Total 5] Ratings 0 Comments 2 Invitations 0 Offline
S
Points 2 [Total 2] Ratings 0 Comments 2 Invitations 0 Offline
S
Points 1 [Total 2] Ratings 0 Comments 1 Invitations 0 Offline
S
R
Points 1 [Total 196] Ratings 0 Comments 1 Invitations 0 Offline
S
Points 1 [Total 2] Ratings 0 Comments 1 Invitations 0 Offline
* Excludes moderators and previous
winners (Include)