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Q: Multiply (y^2-8)(4y^2-3y+1)
A: (y^2 - 8)(4y^2 - 3y + 1) = 4y^4 - 3y^3 + y^2 - 32y^2 + 24y - 8 = 4y^4 - 3y^3 - 31y^2 + 24y - 8
Original conversation
User: Multiply (y^2-8)(4y^2-3y+1)

Weegy: A.y(y + 4) sq ft

Updated 10/29/2014 6:34:00 PM
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [10/29/2014 6:34:00 PM]
Rating
3
(y^2 - 8)(4y^2 - 3y + 1)
= 4y^4 - 3y^3 + y^2 - 32y^2 + 24y - 8
= 4y^4 - 3y^3 - 31y^2 + 24y - 8

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Express using a positive exponent x^-7
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Updated 10/29/2014 6:35:09 PM
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Updated 6/27/2014 10:17:56 AM
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= 2,187/9 = 243
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