Question not found.

Not a good answer? Get an answer now. (FREE)

Rating

There are no new answers.

apply the quadratic formula to find the roots of the given function, and then graph the function:f(x) = x2 + 4

Weegy: f(x)=x^2-4
a=1,b=0,c=-4
x1= (0+sqrt(0+16))/2
x1=2
x2= (0-sqrt(0+16))/2
x2= -2 (More)

Question

All Categories|No Subcategories|Expert Answered

Asked 11/27/2012 11:26:06 AM

0 Answers/Comments

complete the square, and find the roots of the quadratic equation.x2 - 2/3x = 0 x = 1/2 (3-sqrt(37)) x = 1/2 (3+sqrt(37))

Weegy: x^2-(2/3)*x=0
x(x-(2/3)) = 0
so x=0 or x-(2/3)=0
- > x=0 or x=2/3
(More)

Question

All Categories|No Subcategories|Expert Answered

Asked 11/27/2012 1:04:48 PM

0 Answers/Comments

x2 + 16x = 0 You can solve the above these three nethod by 1) factoring, 2) quadratic formula, and 3) completing the square

Weegy: You can solve it through 2) quadratic formula. Ask another one! (More)

Question

All Categories|No Subcategories|Expert Answered

Asked 11/28/2012 3:48:12 PM

0 Answers/Comments

What do we do if the middle term of the quadratic equation (bx) is missing? Who wants to give the following a try?
2x2 + 1 = 0

Weegy: The syntax of quadratic equation that we are familiar with is ax^2+bx+c=0. This actually is an adfected quadratic equation.
The real form is ax^2+b=0, which is a pure quadratic equation.
2x^2+1=0
or, 2x^2=-1.
or, x^2=-1/2
or, x=sqrt(-1/2). (More)

Question

All Categories|No Subcategories|Expert Answered

Asked 11/29/2012 12:10:50 AM

0 Answers/Comments

16,916,784 questions answered

S

R

L

1

1

P

C

1

P

1

1

L

P

C

P

C

1

P

C

L

P

C

1

P

C

Points 1754 [Total 20754]| Ratings 1| Comments 1744| Invitations 0|Offline

There are no comments.