The local zoo has two water tanks for the elephant exhibit that are leaking One water tank contains 12 gal of water and is leaking at a constant rate of 3 gal/h. The second water tank contains 8 gal

of water and is leaking at a constant rate of 5 gal/h. When will the two tanks have the same amount of water? Explain. Let x = the number of hours the tanks are filling and let y = the number of gallons in the tank.
A. In 2 hours, because the solution to the system is (2,18).
B. They will never have the same amount of water because the solution to the system is (–2,18). It is not possible to have time be –2 hours.
C. In –2 hours, because the solution to the system is (–2,18).
D. They will never have the same amount of water because the solution to the system is (–2,18). It is not possible to have –2 gallons in the tanks.

D. They will never have the same amount of water because the solution to the system is (–2,18). It is not possible to have –2 gallons in the tanks.

Expert answered|bluplemud|Points 403|

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Asked 7/25/2012 4:15:16 PM

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What are the solutions of the inequality? Check the solutions. 4x + 6 –3
C. x > –6
D. x **Weegy:** C. x > –6 (More)

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Updated 276 days ago|6/26/2014 5:11:21 PM

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4x + 6 < –6;

4x < -6 - 6;

4x < -12;

x < -12/4;

x < -3

4x < -6 - 6;

4x < -12;

x < -12/4;

x < -3

Added 276 days ago|6/26/2014 5:11:19 PM

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A. 3.50p140; p490
B. 140p3.50; p40
C. 3.50p140; p136.5
D. 3.50p140; p40 **Weegy:** The answer is letter D. 3.50p140; p40 (More)

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Asked 7/22/2012 2:09:09 PM

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How do you write the set in roster form? In set builder notation? Suppose U = {–10, –6, –2, 0, 3, 5} is the universal set and T is the set {–10, –6, 0}. What is the complement of set T?
A. {–2, 3, 5}
B. {–10, –6, 0}
C. {–6, –2, 0, 3, 5}
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Asked 7/22/2012 2:15:03 PM

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What are the solutions of the inequality? Check the solutions. 4x + 6 –3
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Asked 7/22/2012 2:02:02 PM

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Check the solutions. 4x + 6 –3
C. x > –6
D. x **Weegy:** A (More)

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