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How many solutions does the following system of equations have? 6x - 3y = 6 2x - y = 2 (Points : 5) zero one two an infinite number
the following system of equations have c) two solutions
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User: How many solutions does the following system of equations have? 6x - 3y = 6 2x - y = 2 (Points : 5) zero one two an infinite number

Weegy: the following system of equations have c) two solutions
uxiali|Points 885|

User: If the system of equations given below is solved using the substitution method, what is the equation that results from solving the second equation for y, and substituting into the first equation? 3x - 2y = 7 x - y = 5 (Points : 5) y + 15 = 7 x + 10 = 7 y = x - 5 x - 10 = 7

Weegy: 3x - 4 = 2x - 10 3x - 2x = -10 + 4 x = -6
Expert answered|gevgev03|Points 20|

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Asked 12/1/2012 7:45:48 PM
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All relations are functions. (Points : 5) True False
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Updated 280 days ago|12/19/2015 11:09:15 AM
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All relations are functions. FALSE.
Added 280 days ago|12/19/2015 11:09:15 AM
This answer has been confirmed as correct, not copied, and helpful.
. Solve the following word problem (Hint: setup and solve a system of equations): One number plus twice another number gives a sum of 42. The difference of these same two numbers equals –3. Find the two numbers (Points : 5) The numbers are 12 and 15. The numbers are 11 and 14. The numbers are 13 and 16. This problem has no solution.
Weegy: The numbers are 12 and 15. Equations: x + 2y = 42 x - y = -3 - - - - - - - - - Subtract and solve for "y": 3y = 45 y = 15 - - Solve for "x": x - y = -3 x -15 = -3 x = [ 12 ] (More)
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Asked 12/1/2012 7:56:08 PM
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13. If the system of equations given below is solved using the substitution method, what is the equation that results from solving the second equation for y, and substituting into the first equation? 3x - 2y = 7 x - y = 5 (Points : 5) y + 15 = 7 x + 10 = 7 y = x - 5 x - 10 = 7
Weegy: The answer to your question , the equation that results from solving the second equation for y, and substituting into the first equation is 3x - 2y = 7 ; x - y = 5 (More)
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Asked 12/1/2012 8:01:19 PM
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