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How many moles of aluminum are needed to react completely with 2.4 mol of FeO? 2Al(s)+3FeO(s)=3Fe(s)+Al2O3(s) a 1.2 mol b 0.8 mol c 1.6 mol d 2.4 mol
0.8 mol aluminum are needed to react completely with 2.4 mol of FeO. The balanced equation tells you that 2 moles of Al will react with 3 moles of FeO Let x moles of Al react with 1.2 moles of FeO x/1.2 = 2/3 x = 2x1.2/3 = 2.4/3 = 0.8 moles of [ Al ]
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Asked 2/25/2013 7:42:20 PM
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