Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2? The equation for the complete combustion of methane is:
CH4(g) + 2O2(g) ? CO2(g) + 2H2O(l)

Q: Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2? The equation for the complete combustion of methane is:
CH4(g) +

2O2(g) ? CO2(g) + 2H2O(l)

A: The answer is "16.0 g CH4 over 1 mol CH4"
You need to convert to moles because the grams cannot be compared directly based upon the reaction, but you know that for every mole of CH4 used, one mole of CO2 is produced. [ Converting CH4 to moles tells you how many moles of CO2 you produce, which can be converted to a mass. ]

Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2? The equation for the complete combustion of methane is: CH4(g) + 2O2(g) ? CO2(g) + 2H2O(l)

Original conversation

User: Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2? The equation for the complete combustion of methane is:
CH4(g) + 2O2(g) ? CO2(g) + 2H2O(l)

Weegy: The answer is "16.0 g CH4 over 1 mol CH4"
You need to convert to moles because the grams cannot be compared directly based upon the reaction, but you know that for every mole of CH4 used, one mole of CO2 is produced. [ Converting CH4 to moles tells you how many moles of CO2 you produce, which can be converted to a mass. ] bongche|Points 3864|

User: what is conserved in this reaction? h2 g cl2 g ? 2hcl g

Weegy: You need to find a table in your book that lists g,h,and s for each of these gases. I'd write them out above each gas, and then work it like a math problem. If s for HCL is 5, then the total s is 2*5 for two moles. [ If s for H2 is 1 and s for Cl2 is 3, then the delta s is 5-(3+1) = 1
The same goes for g and h.
Look at your answers for a to determine part b. If the delta s is positive (molecules becoming more disordered) and heat is released (positive delta h) then the reaction shifts toward the products, to make 2 moles of HCL from 1 mole each of the reactants. ] hsmily|Points 25|

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