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Q: Find an equation of the circle that has center (1, -2) and passes through (5,-6).
A: The equation of the circle that has center (1, -2) and passes through (5, -6) is (x - 1)^2 + (y + 2)^2 = 32.
Question
Updated 7/17/2014 12:17:30 AM
Rating
3
The equation of the circle that has center (1, -2) and passes through (5, -6) is (x - 1)^2 + (y + 2)^2 = 32.

Confirmed by andrewpallarca [7/17/2014 12:39:21 AM]

Questions asked by the same visitor
Find an equation of the circle that has center (-4,3) and passes through (4,4) .
Question
Updated 7/17/2014 12:20:26 AM
The equation of the circle that has center (-4,3) and passes through (4,4) is (x + 4)^2 + (y - 3)^2 = 65.
Confirmed by andrewpallarca [7/17/2014 12:39:44 AM]
Find an equation of the circle that has center (-5,4) and passes through (2,-3).
Question
Updated 7/17/2014 12:14:58 AM
The equation of the circle that has center (-5,4) and passes through (2,-3) is (x + 5)^2 + (y - 4)^2 = 98.
Confirmed by andrewpallarca [7/17/2014 12:39:19 AM]
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