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. How many liters of NH3, at STP, will react with 5.3 g O2 to form NO2 and water? 4NH3(g) +7O2(g) à 4NO2 + 6H2O(g) A. 0.00423 L B. 3.03 L C.
2.12 L D. 6.49 L
use molar mass to finf moles of O2: 5.3 g O2 @ 32.0 g/mol = 0.1656 moles of O2 use this ratio: 4NH3(g) + 7O2(g) - > , [ to find moles of NH3: 0.1656 mol O2 @ 4 mole NH3 / 7 mol O2 = 0.09464 moles of NH3 using the "molar volume " ratio for gases @ STP, find the litres of NH3: 0.09464 moles NH3 @ 22.4 litres / mole STP = 2.12 litres the answer is 2.1 litres ]
Expert answered|jbgingz|Points 199|
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Asked 5/19/2013 7:25:11 AM
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In any physical or chemical change, mass is not conserved. This statement is B. False. According to the law of conservation of mass, mass can neither be created nor destroyed in any physical change or chemical reaction.
Added 5/19/2013 2:36:23 PM
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