. How many liters of NH3, at STP, will react with 5.3 g O2 to form NO2 and water?
4NH3(g) +7O2(g) à 4NO2 + 6H2O(g)
use molar mass to finf moles of O2:
5.3 g O2 @ 32.0 g/mol = 0.1656 moles of O2
use this ratio: 4NH3(g) + 7O2(g) - > , [ to find moles of NH3:
0.1656 mol O2 @ 4 mole NH3 / 7 mol O2 = 0.09464 moles of NH3
using the "molar volume " ratio for gases @ STP, find the litres of NH3:
0.09464 moles NH3 @ 22.4 litres / mole STP = 2.12 litres
the answer is 2.1 litres ]
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