. How many liters of NH3, at STP, will react with 5.3 g O2 to form NO2 and water? 4NH3(g) +7O2(g) à 4NO2 + 6H2O(g) A. 0.00423 L B. 3.03 L C.
2.12 L D. 6.49 L
use molar mass to finf moles of O2: 5.3 g O2 @ 32.0 g/mol = 0.1656 moles of O2 use this ratio: 4NH3(g) + 7O2(g) - > , [ to find moles of NH3: 0.1656 mol O2 @ 4 mole NH3 / 7 mol O2 = 0.09464 moles of NH3 using the "molar volume " ratio for gases @ STP, find the litres of NH3: 0.09464 moles NH3 @ 22.4 litres / mole STP = 2.12 litres the answer is 2.1 litres ]
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If the percent (mass/mass) for a solute is 4% and the mass of the solution is 200 g, what is the mass of solute in solution? A. 50 g B. 80 g C. 800 g D. 8.0 g
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Updated 1/4/2015 7:29:26 PM
If the percent (mass/mass) for a solute is 4% and the mass of the solution is 200 g, the mass of solute in solution is 4%*200 g = 8.0 g
Confirmed by andrewpallarca [1/4/2015 7:33:40 PM]
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