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. How many liters of NH3, at STP, will react with 5.3 g O2 to form NO2 and water? 4NH3(g) +7O2(g) à 4NO2 + 6H2O(g) A. 0.00423 L B. 3.03 L C.
2.12 L D. 6.49 L
use molar mass to finf moles of O2: 5.3 g O2 @ 32.0 g/mol = 0.1656 moles of O2 use this ratio: 4NH3(g) + 7O2(g) - > , [ to find moles of NH3: 0.1656 mol O2 @ 4 mole NH3 / 7 mol O2 = 0.09464 moles of NH3 using the "molar volume " ratio for gases @ STP, find the litres of NH3: 0.09464 moles NH3 @ 22.4 litres / mole STP = 2.12 litres the answer is 2.1 litres ]
Expert answered|jbgingz|Points 199|
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Asked 5/19/2013 7:25:11 AM
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Added 5/19/2013 2:36:23 PM
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