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If water is added to 50 ml of a 0.04 M solution so that it fills a 200 ml beaker, what is the final concentration?
Weegy: Please give us the question before this one so we can answer properly. User: 100. g of C12H22O11 (molecular weight = 342.28 g/mole) in 1.15 liters of solvent Weegy: Yeah molarity is just how many moles of the solute are dissilved in 1 liter of solvent. we have 100 grams of the sugar which hass a molar mass of 342.28. so just do 100 / 342.28 and you get 0.292158467 moles of the sugar since it's dissolved in [ 1.15 liters of ... (More)
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Asked 2/8/2012 8:40:54 AM
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The molecular weight of NaCl is 58.44 grams/mole. If you had a 1.0 molar solution (1.0 M), you would have to put 58.44 g of salt in 1.0 liter of solution User: Now dilute 10.0 mL of the 0.50 M NaCl by adding distilled water until 100 mL of solution are produced. Do the 100 mL of diluted NaCl have more, less, or the same quantity of NaCl as the original 10.0 mL of 0.50 M NaCl?
Weegy: Fresh water has a density of 1.0 while salt water has a density of 1.025. From this, you can see that salt water is slightly heavier than fresh water. The ratio between the two is 41:40. The result would approximately 95 grams. User: Concerning the 10.0 mL of 0.50 M NaCl diluted to 100 mL of solution When a solution is diluted, does the dilution change the number of grams dissolved? User: When a solution is diluted does the dilution ... (More)
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Asked 2/8/2012 8:47:06 AM
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