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If water is added to 50 ml of a 0.04 M solution so that it fills a 200 ml beaker, what is the final concentration?
Weegy: Please give us the question before this one so we can answer properly. User: 100. g of C12H22O11 (molecular weight = 342.28 g/mole) in 1.15 liters of solvent Weegy: Yeah molarity is just how many moles of the solute are dissilved in 1 liter of solvent. we have 100 grams of the sugar which hass a molar mass of 342.28. so just do 100 / 342.28 and you get 0.292158467 moles of the sugar since it's dissolved in [ 1.15 liters of solvent. do 0.292158467 / 1.15 = 0.254050841 so the molarity is 0.254 M or it just means there is 0.254 moles of sugar dissolved in every liter of water ] (More)
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Asked 2/8/2012 8:40:54 AM
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The molecular weight of NaCl is 58.44 grams/mole. If you had a 1.0 molar solution (1.0 M), you would have to put 58.44 g of salt in 1.0 liter of solution User: Now dilute 10.0 mL of the 0.50 M NaCl by adding distilled water until 100 mL of solution are produced. Do the 100 mL of diluted NaCl have more, less, or the same quantity of NaCl as the original 10.0 mL of 0.50 M NaCl?
Weegy: Fresh water has a density of 1.0 while salt water has a density of 1.025. From this, you can see that salt water is slightly heavier than fresh water. The ratio between the two is 41:40. The result would approximately 95 grams. User: Concerning the 10.0 mL of 0.50 M NaCl diluted to 100 mL of solution When a solution is diluted, does the dilution change the number of grams dissolved? User: When a solution is diluted does the dilution change the number of grams dissolved? User: 6.02 x 1022 molecules of HCl (molecular weight = 36.5 g/mole) in 2.0 liters of water Weegy: molarity = number of moles of solute / volume of solution in liters 6.02 x 1022 molecules of HCl = 6.02 x 1022 / 6.02 x 1023 moles of HCl moles of HCl = 1/10 = .1 volume of solution = 2 liters molarity = .1/2 = .05 molar source: yahoo User: 4.32 x 102 moles of CH3COOH in 20.0 liters of water Weegy: C = n/V C= 4.32 x 10^2/ 20.0L C= 21.6M User: Consider again the solution made by diluting 10.0 mL of the 0.50 M NaCl by adding distilled water until 100 mL of solution are produced. Has the concentration of the diluted salt solution increased, decreased, or remained constant? Weegy: Fresh water has a density of 1.0 while salt water has a density of 1.025. From this, you can see that salt water is slightly heavier than fresh water. The ratio between the two is 41:40. The result would approximately 95 grams. User: 29 g of NaCl in 0.25 liters of water (The molecular weight of NaCl is 58.44 g/mole.) Weegy: Convert 29. grams to moles, so 29/58.44 gives .496moles. Molarity is moles/liters, so .496/.25 gives 2.0M using 2 sig figs. source: yahoo User: Concerning the 10.0 mL of 0.50 M NaCl to 100 mL of solution Does dilution change the concentration? Weegy: These questions test your use of dimensional analysis. [ 0.50M is a ratio meaning you have 0.50Moles of a substance per Liter. 10.0ml substance | 1L | 0.05 mol | = 0.01 Moles of substance contained in 10.0ml - - - - - - ... (More)
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Asked 2/8/2012 8:47:06 AM
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