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Q: (6x^2 – 25x – 10) ÷ (3x + 2) (show steps)
A: (6x^2 – 25x – 10) ÷ (3x + 2) = (6x^2/3x + 2) + (-25x/3x + 2) + (-10/3x + 2) = 2x - 29/3 R. 28/3
Question
Updated 5/24/2016 12:47:24 PM
Rating
3
(6x^2 – 25x – 10) ÷ (3x + 2)
= (6x^2/3x + 2) + (-25x/3x + 2) + (-10/3x + 2)
= 2x - 29/3 R. 28/3

Questions asked by the same visitor
Simplify (9x^2y^4)^3
Question
Updated 9/2/2014 11:25:03 AM
(9x^2y^4)^3 = 729x^6y^12
Solve for X: X2 + 3x – 28 = 0 (show steps)
Question
Updated 8/17/2014 6:24:47 PM
x^2 + 3x - 28 = 0;
(x + 7)(x - 4) = 0;
x + 7 = 0; x = -7;
x - 4 = 0; x = 4
x = {-7, 4}
Confirmed by andrewpallarca [8/17/2014 6:30:48 PM]
pemdas : 6 x 3 + 10 ÷ 2
Weegy: 6 x 3 + 10 ÷ 2 = 18+5 = 23 (More)
Question
Updated 2/13/2014 3:15:22 PM
pemdas: 5 + 2^2 x 3 ÷ (5 - 2)
Question
Updated 7/7/2014 7:20:58 PM
5 + 2^2 x 3 ÷ (5 - 2)

= 5 + 4 x 3 ÷ (3)

= 5 + 12 ÷ 3

= 5 + 4

= 9
x^2 + 9x+ 14 A. (x + 7)(x - 2) B .(x + 7)(x + 2) C. (x + 14)(x + 1)
Question
Updated 7/7/2014 7:23:03 PM
x^2 + 9x + 14 = (x + 7)(x + 2)
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