Use the algebraic tests to check for symmetry with respect to both axes and the origin: x - y^2 = 13?
first, always take one of these stupid equations and solve for y.. makes life easier x-y^2=13 x-13=y^2 sqrt(x-13)=y now you can say: sqrt(x-13)=f(x) to check for symmetry to Y.. f(-x)= sqrt(-x-13).. ...
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User: Use the algebraic tests to check for symmetry with respect to both axes and the origin: x - y^2 = 13?

Weegy: first, always take one of these stupid equations and solve for y.. makes life easier x-y^2=13 x-13=y^2 sqrt(x-13)=y now you can say: sqrt(x-13)=f(x) to check for symmetry to Y.. f(-x)= sqrt(-x-13).. if the right side of the equation is the same as the original equation(sqrt(x-13)) then it is symetric to y(also called "even"), which this equation isn't for x symmetry, -f(x)=-(sqrt(x-13)).. is it exactly opposite the original equation? meaning, all positive signs are now negative.. no it isn't. since it is neither of those, it isn't symmetrical with the origin either.(both cases have to be true for it to be symmetrical to origin) hope this helps

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Weegy: Use the algebraic tests to check for symmetry with respect to both axes and the

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