2x + y = 3 x = 2y - 1 substitute x in the first equation the result is: 2(2y - 1) + y = 3 4y - 2 + y = 3 5y = 3 + 2 = 5 y = 5/5 = 1 x = 2(1) - 1 = 2 - 1 = 1 The solution for the system 2x + y = 3 x = 2y - 1 is (1, 1)

Added 11/18/2014 11:47:54 PM

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