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Q: Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight.
A: Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight. Call the numbers x and x+2. (3/7)x + (x+2)/3 = 38 Multiply both ides by 21 9x + 7x + 14 = 798 16x = [ 784 x = 49 The numbers are 49 and 51. ]
Original conversation
User: Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight.

Weegy: Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight. Call the numbers x and x+2. (3/7)x + (x+2)/3 = 38 Multiply both ides by 21 9x + 7x + 14 = 798 16x = [ 784 x = 49 The numbers are 49 and 51. ]
rugmaker|Points 3178|

User: The ages of two brothers are in the ratio two to three, but in eight years, the ratio of their ages will be three to four. What is the age of the younger brother?

Weegy: The answer is C) 24 let x = age of younger bro ley y = age of older bro x/y = 2/3 - - > x = 2y/3 eq.1 x+8 / y+8 = 3/4 eq.2 sub eq.1 into eq.2: (2y/3) + 8 / y+8 = 3/4 (2y+24)/3 / y+8 = 3/4 2y + 24 / 3(y+8) = 3/4 2y+24 / 3y+24 = 3/4 4(2y+24) = [ 3(3y+24) 8y+96 = 9y+72 24=y x=2y/3=2*24/3=16 ]
dennis003|Points 1030|

User: Twenty pounds of a salt-water solution contains fifteen percent salt. How much salt is in the water?

Weegy: 30 pounds of the solution contain 4.5 pounds of salt (15%), to get that to 10% you would have to add 15 more pounds of water so that you have 4.5 of sale in a total of 45 pounds of salt and water solution. Answer = add 15 pounds of water
jeifunk|Points 10006|

User: Twenty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to twelve percent salt?

Weegy: 3lb
moja2013|Points 71|

User: The distance between two cities is ninety miles, and a woman drives from one city to the other at a rate of 45 mph. At what rate must she return if the total travel time is three hours and forty minutes?

Weegy: 1st leg DATA: distance = 90 mi ; rate = 45 mph ; time = d/r = 2 hrs. - - 2nd leg DATA: distance = 90 mi ; time = [3 2/3 - 2] = 1 2/3 hrs; rate = 90/(5/3) = 54 mph - - - - Ans: 54 mph ====================== Cheers, Stan H.
manimic|Points 140|

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