Q: Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight.

A: Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight.
Call the numbers x and x+2.
(3/7)x + (x+2)/3 = 38
Multiply both ides by 21
9x + 7x + 14 = 798
16x = [ 784
x = 49
The numbers are 49 and 51.
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Asked 8/6/2013 2:53:15 PM

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