Q: When the following quadratic equation is written in general form, what is the value of "c"?

A: Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. [ But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring. While factoring may not always be successful, the Quadratic Formula can always find the solution.
The Quadratic Formula uses

the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients". The Formula is derived from the process of completing the square, and is formally stated as:
For ax2 + bx + c = 0, the value of x is given by:
x = [ -b ? sqrt(b^2 - 4ac) ] / 2a
For the Quadratic Formula to work, you must have your equation arranged in the form "(quadratic) = 0". Also, the "2a" in the denominator of the Formula is underneath everything above, not just the square root. And it's a "2a" under there, not just a plain "2". Make sure that you are careful not to drop the square root or the "plus/minus" in the middle of your calculations, or I can guarantee that you will forget to "put them back" on your test, and you'll mess yourself up. Remember that "b2" means "the square of ALL of b, including its sign", so don't leave b2 being negative, even if b is negative, because the square of a negative is a positive. ]

martinfrank|Points 20|

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A word in the predicate that receives the action expressed by the verb is known as the _____.

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Updated 3/18/2014 6:36:41 PM

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A word in the predicate that receives the action expressed by the verb is known as the DIRECT OBJECT.

Added 3/18/2014 6:36:41 PM

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thesis statement must always _____.
come at the end of the introduction
make an assertion to be proven by the body of the text
be the first sentence of a text
both a and b
b and c
none of the above

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Updated 7/31/2015 4:23:48 AM

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The series 10 + 17 + 24 + 31 + 38 + . . . is:
arithmetic

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Updated 55 days ago|1/22/2018 3:56:19 AM

1 Answer/Comment

The series 10 + 17 + 24 + 31 + 38 + . . . is: arithmetic sequence.

Added 55 days ago|1/22/2018 3:56:19 AM

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Describe the following sequence as arithmetic, geometric or neither.
2, 4, 6, 12, 14. . . .
arithmetic
geometric
neither **Weegy:** The series 6 + 6 + 6+ 6 + 6 + . . . is:arithmetic series , where common diff. = 0 (More)

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Updated 1/10/2015 6:48:27 AM

1 Answer/Comment

The following sequence 2, 4, 6, 12, 14. . . . is neither arithmetic nor geometric .

Because it has not common ratio or common difference .

Because it has not common ratio or common difference .

Added 1/10/2015 6:48:27 AM

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Confirmed by sujaysen [1/10/2015 12:05:24 PM]

Find the GCF of the given polynomial User: Find the GCF of the given polynomial 16a4b4 + 32a3b5 - 48a2b6
**Weegy:** 16a2b4 **User:** Find the GCF of the following literal terms m7n4p3 and mn12p5
**Weegy:** m7n12p3 **User:** Simplify p(p - q) - q(q - p).
**Weegy:** b(a + b) - a(a - b) is equal to n^2-a^2+2ab or -a^2+2ab+b^2. SOLUTION: b(a + b) - a(a - b) ab+b^2-a^2+ab b^2-a^2+ab+ab n^2-a^2+2ab or -a^2+2ab+b^2 **User:** Find the product
-7(8 + k)
**Weegy:** I think your equation is incomplete. **User:** 4x 3 y 2(7xy 4)
(More)

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Updated 6/25/2014 3:17:15 AM

4 Answers/Comments

The GCF of m^7n^4p^3 and mn^12p^5 is mn^4p^3.

Added 6/25/2014 3:15:23 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/25/2014 8:14:59 AM]

p(p - q) - q(q - p)

= p^2 - pq - q^2 + pq

= p^2 - q^2

= p^2 - pq - q^2 + pq

= p^2 - q^2

Added 6/25/2014 3:16:16 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/25/2014 8:15:11 AM]

-7(8 + k) = -56 - 7k

Added 6/25/2014 3:16:42 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/25/2014 8:15:32 AM]

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