Simplify the expression.
4 square root 6+5 square root 6

4 square root 6 + 5 square root 6 = 4 sqrt 6 + 5 sqrt 6 = 9 sqrt 6

Expert answered|Micharnaezz|Points 40|

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Find the sample space for tossing 2 coins. Then find P(exactly 1 head). A. 1/8 B. 1/2 C. 3/4 D. 1/4 **Weegy:** exactly 4 heads in 6 flips of a fair coin? The probability of a head in one flip is 1/2. The probability of HHHHTT is (1/2)6 = 1/64 ... [ 1,2,3,4,5 ... sample space when tossing a ... ] (More)

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Asked 4/4/2013 7:17:45 PM

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In how many ways could you choose two different letters from the letters C, O, U, N, T?
A. 60 ways
B. 20 ways
C. 120 ways
D. 10 ways
**Weegy:** C 120 (More)

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Asked 4/4/2013 7:27:59 PM

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Use the Counting Principle to find the probability of choosing the 8 winning lottery numbers when the numbers are chosen at random from 0 to 9. A. 1/10,000,000 B. 1/1,000,000,000 C. 1/100,000,000 D. 1/43,046,721 **Weegy:** Use the Counting Principle to find the probability. [ choosing the 8 winning lottery numbers when the numbers are chosen at random from 0 to 9
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# of ways to choose the winning numbers: 8*7*6*5*4*3*2*1
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# of possible outcomes: 10*10*10*10*10*10*10*10
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P(choose winning number) = 8!/10^8 = 0.0004032 ] (More)

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Asked 4/4/2013 7:31:42 PM

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Draw the box-and-whisker plot for the data.
21 29 25 20 36 28 32 35 28 30 29 25 21 35 26 35 20 19
A.
B.
C.
D. none of these
**Weegy:** D. none of these (More)

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Asked 4/4/2013 7:37:55 PM

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Simplify.
17C4 A. 2,380
B. 680
C. 57,120
D. 4,760
**Weegy:** A. 2,380 (More)

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Updated 4/4/2013 8:21:38 PM

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17C4 = 17! / ( 4! (17 - 4)! )

17C4 = ( 17! ) / ( 4! * 13! )

17C4 = (17 * 16 * 15 * 14) / (4 * 3 * 2 * 1)

17C4 = 2380

17C4 = ( 17! ) / ( 4! * 13! )

17C4 = (17 * 16 * 15 * 14) / (4 * 3 * 2 * 1)

17C4 = 2380

Added 4/4/2013 8:21:38 PM

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