Q: Simplify: 3(x + 4) - 2(x - 2)
a. x + 8
b. -5x + 16
c. x + 16
d. 5x + 16

A: 3(x + 4) - 2(x - 2) =3x+12-2(x-2) =3x+12-(2x-4) =x+16

thederby|Points 1238|

Question

Asked 6/23/2012 5:49:35 PM

Updated 6/30/2014 12:55:26 AM

1 Answer/Comment

This conversation has been flagged as incorrect.

Flagged by jeifunk [6/30/2014 12:55:26 AM]

Rating

3

3(x + 4) - 2(x - 2)

=3x+12-2(x-2)

=3x+12-(2x-4)

=x+16

=3x+12-2(x-2)

=3x+12-(2x-4)

=x+16

Added 6/30/2014 12:55:23 AM

This answer has been confirmed as correct and helpful.

Simplify: -3(2z + 7)
a. -6z + 7
b. -6z - 21
c. -6z + 21
d. -27z

Question

Not Answered

Updated 8/5/2014 11:43:58 PM

1 Answer/Comment

-3(2z + 7) = -6z - 21

Added 8/5/2014 11:43:58 PM

This answer has been confirmed as correct and helpful.

Simplify: -3(2z + 7) **Weegy:** -3(2z + 7)
= -6z - 21 (More)

Question

Expert Answered

Updated 5/1/2014 12:58:49 AM

0 Answers/Comments

Simplify: 3(x + 4) - 2(x - 2) a. x + 8 b. -5x + 16 c. x + 16 d. 5x + 16
**Weegy:** 3(x+4)-2(x-2)*ax+8b-5x+16cx+16dx+16
Multiply 3 by each term inside the parentheses (x+4).
3(x)+3(4)-2(x-2)*ax+8b-5x+16cx+16dx+16
Multiply 3 by the x inside the parentheses.
3*x+3(4)-2(x-2)*ax+8b-5x+16cx+16dx+16
Multiply 3 by x to get [ 3x.
3x+3(4)-2(x-2)*ax+8b-5x+16cx+16dx+16
Multiply 3 by the 4 inside the parentheses.
3x+3*4-2(x-2)*ax+8b-5x+16cx+16dx+16
Multiply 3 by 4 to get 12.
3x+12-2(x-2)*ax+8b-5x+16cx+16dx+16
Multiply -2 by each term inside the parentheses (x-2).
3x+12-2(x)-2(-2)*ax+8b-5x+16cx+16dx+16
Multiply -2 by the x inside the parentheses.
3x+12-2*x-2(-2)*ax+8b-5x+16cx+16dx+16
Multiply -2 by x to get -2x.
3x+12-2x-2(-2)*ax+8b-5x+16cx+16dx+16
Multiply -2 by the -2 inside the parentheses.
3x+12-2x-2*-2*ax+8b-5x+16cx+16dx+16
Multiply -2 by -2 to get 4.
3x+12-2x+4*ax+8b-5x+16cx+16dx+16
Multiply 4 by ax to get 4ax.
3x+12-2x+4ax+8b-5x+16cx+16dx+16
According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, x is a factor of both 3x and -2x.
(3-2)x+12+4ax+8b-5x+16cx+16dx+16
To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of 3 and -2 and give the result the same sign as the integer with the greater absolute value.
(1)x+12+4ax+8b-5x+16cx+16dx+16
Remove the parentheses.
x+12+4ax+8b-5x+16cx+16dx+16
According to the distributive property, for any numbers a, b, and c, a(b+c)=ab+ac and (b+c)a=ba+ca. Here, x is a factor of both x and -5x.
(1-5)x+12+4ax+8b+16cx+16dx+16
To add integers with different signs, subtract their absolute values and give the result the same sign as the integer with the greater absolute value. In this example, subtract the absolute values of 1 and -5 and give the result the same sign as the integer with the greater absolute value.
(-4)x+12+4ax+8b+16cx+16dx+16
Remove the parentheses.
-4x+12+4ax+8b+16cx+16dx+16
Add 16 to 12 to ... (More)

Question

Expert Answered

Updated 6/24/2012 11:10:49 PM

4 Answers/Comments

c. x + 16

3(x + 4) - 2(x - 2) = 3x + 12 - 2x + 4 = x + 16.

Source:

3(x + 4) - 2(x - 2) = 3x + 12 - 2x + 4 = x + 16.

Source:

Added 6/23/2012 6:25:25 PM

This answer has been confirmed as correct and helpful.

Rated bad by John@evang, Confirmed by jeifunk [6/30/2014 12:54:32 AM]

Sorry for the error.

Added 6/24/2012 4:27:26 PM

This answer has been flagged as incorrect.

Flagged by jeifunk [6/30/2014 12:53:41 AM]

Ans-C: x + 16 =

3(x+4)-2(x-2)=

3x + 12 - 2x + 4=

collect the like terms.

3x - 2x + 12 + 4=

x + 16 .

3(x+4)-2(x-2)=

3x + 12 - 2x + 4=

collect the like terms.

3x - 2x + 12 + 4=

x + 16 .

Added 6/24/2012 7:24:15 PM

This answer has been flagged as incorrect.

Confirmed by jeifunk [6/30/2014 12:54:19 AM], Unconfirmed by jeifunk [6/30/2014 12:54:28 AM], Flagged by jeifunk [6/30/2014 12:54:34 AM], Unflagged by jeifunk [6/30/2014 12:54:45 AM], Flagged by jeifunk [6/30/2014 12:54:48 AM]

Combine like terms: 4x + 2y - 3x + 7y **Weegy:** 4x + 2y - 3x + 7y = x + 9y (More)

Question

Expert Answered

Updated 4/28/2014 4:49:02 PM

0 Answers/Comments

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