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What is the midpoint of a segment whose endpoints are (-12, 8) and the origin?
A) (0, 0)
B) (4, 6)
C) (-6, 4)
D) (6, -4)

Question

Not Answered

Updated 7/27/2014 1:12:11 PM

1 Answer/Comment

What is the distance between the points (6, 32) and (-8, -16)?
A) 63
B) 48
C) 125
D) 50
**Weegy:** D) 50
**User:** What is the distance between the points (10, 2) and (14, 5)?
A) 1
B) 3
C) 5
D) 10
**Weegy:** C) 5 **User:** What is the midpoint of a segment whose endpoints are (-12, -7) and
(8, -11)?
A) (-10, -2)
B) (9, -2)
C) (-2, -9)
D) (2, 10)
**Weegy:** C) (-2, -9) **User:** What is the midpoint of a segment whose endpoints are (3, 7) and (7, 3)?
A) (2, -2)
B) (5, -5)
C) (2, 2)
D) (5, 5)
(More)

Question

Expert Answered

Updated 7/28/2011 9:08:15 AM

1 Answer/Comment

What is the midpoint of a segment whose endpoints are (3, 7) and (7, 3)?
A) (2, -2)
B) (5, -5)
C) (2, 2)
D) (5, 5)
**Weegy:** D) (5, 5) If satisfied with the response, please click "Good" (More)

Question

Expert Answered

Updated 7/14/2014 2:56:20 AM

1 Answer/Comment

The \midpoint of a segment whose endpoints are (3, 7) and (7, 3) is (5, 5).

((x1+x2)/2, (y1+y2)/2)

= ((3 + 7)/2, (7 + 3)/2)

= (10/2, 10/2)

= (5, 5)

((x1+x2)/2, (y1+y2)/2)

= ((3 + 7)/2, (7 + 3)/2)

= (10/2, 10/2)

= (5, 5)

Added 7/14/2014 2:56:20 AM

This answer has been confirmed as correct, not copied, and helpful.

What is the distance between the points (-19, -4) and (11, 12)?
A) 30
B) 34
C) 48
D) 17

Question

Not Answered

Updated 7/14/2014 2:59:26 AM

1 Answer/Comment

The distance between the points (-19, -4) and (11, 12) is 34.

Added 7/14/2014 2:59:26 AM

This answer has been confirmed as correct, not copied, and helpful.

What is the midpoint of a segment whose endpoints are (4, 0) and (0, -2)?
A) (2, -1)
B) (4, 2)
C) (2, -4)
D) (1, -2)
**Weegy:** (More)

Question

Expert Answered

Updated 7/14/2014 2:58:03 AM

3 Answers/Comments

The midpoint of a segment whose endpoints are (4, 0) and (0, -2) is (2, -1).

((x1+x2)/2, (y1+y2)/2)

= ((4 + 0)/2, (0 - 2)/2)

= (4/2, -2/2)

= (2, -1)

((x1+x2)/2, (y1+y2)/2)

= ((4 + 0)/2, (0 - 2)/2)

= (4/2, -2/2)

= (2, -1)

Added 7/14/2014 2:57:59 AM

This answer has been confirmed as correct, not copied, and helpful.

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