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Q: During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acceleration? Show your work
A: a = (v2 - v1)/t = (10 - 6)/2 = 2 m/sec/sec (average acceleration).
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Original conversation
User: During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acceleration? Show your work

Weegy: a = (v2 - v1)/t = (10 - 6)/2 = 2 m/sec/sec (average acceleration).
lloyde|Points 0|

User: If you ride your bike at an average speed of 4 km/h and need to travel a total distance of 28 km, how long will it take you to reach your destination? Show your work.

Weegy: Time taken = Distance/Speed. 28/4 = 7 hours.
lena.G|Points 231|

User: A small dog is trained to jump straight up a distance of 1.2 m. How much kinetic energy does the 7.2-kg dog need to jump this high? (The acceleration due to gravity is 9.8 m/s2.) Show your work.

Weegy: Formula: s=ut+.5at^2. s (distance traveled) = 1.2 m. u (initial velocity which) = 0. t (time) = 0.5 sec. a (acceleration) = 10 m/s^2. Find velocity v = s/t = 1.2/.5 = 2.4 m/sec. then kinetic energy= 0.5mv^2. Where m is mass, v is velocity. [ k.e. = 20.74 joules. ]
lena.G|Points 231|

User: As 390 g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment. What is the temperature change of the milk? The specific heat of milk is 3.9 J/g•°C. Show your work.

Weegy: As 390 g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment. What is the temperature change of the milk? The specific heat of milk is 3.9 J/g??C. dT = 30000/(390*3.9) = 19.72 Degs C
debralev143|Points 160|

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Asked 6/3/2013 6:40:47 PM
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