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A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice are homozygous black and 24% are heterozygous black, what would be the
frequency of each allele? (p + q = 1, p2 + 2pq + q2 = 1) A. p= 0.65, q= 0.35 B. p= 0.25, q= 0.75 C. p =0.4 q=0.6
B. p= 0.25, q= 0.75
Expert answered|patrick_hustla|Points 110|
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Asked 6/27/2012 9:08:25 AM
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A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice are homozygous black and 24% are heterozygous black, what would be the frequency of each allele?
Weegy: If a parent who is homozygous dominant for a trait mates with a homozygous recessive person, then all of their children will express the dominant allele?s phenotype. Black is the dominant phenotype, therefore they would be born black. (More)
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Asked 6/27/2012 8:59:44 AM
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