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A hydraulic system for a dentist's chair is designed to be able to lift 3,112 newtons. The surface area over which this force is applied is 707 cm2. What force must be applied to the activator end of the system if the button has a surface area of 3.14 cm2?
700,700 N
1.41 N
0.0724 N
13.8 N

Weegy: 3112 : 0.707 dm^2 = x : 0.00314 dm^2
x = 13.8 N
area=58.8cm^2=.0058 m^2
pressure=20275 Pascals or 2 N/cm^2
So the units on your choices are incorrect. (More)

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Asked 9/19/2012 10:59:36 AM

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A solid object has a density of 2.85 g/cm3. According to Archimedes, what can be done to make this object float in water?
Nothing can make this object float because it is too dense.
Cut the object down to one third of its current size.
Reshape the object so that it displaces more than its own weight of water.
Decrease the density of the object by making its volume smaller.

Weegy: The answer is 585 g. (More)

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Asked 9/19/2012 11:12:29 AM

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143°C = _____
-130 K
0 K
143 K
416 K

Weegy: 143°C = 416 K. (More)

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Asked 9/20/2012 7:29:56 AM

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100 K = _____
-173°C
0°C
100°C
373°C

Weegy: 100 K = -173°C (More)

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Asked 9/20/2012 7:27:03 AM

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The freezing temperature of water is zero on both the Kelvin and Celsius scales.
True
False

Weegy: No. (More)

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Updated 9/21/2012 9:52:18 AM

4 Answers/Comments

0 °C = 273.15 K.

This definition fixes the magnitude of both the degree Celsius and the kelvin as precisely 1 part in 273.16 (approximately 0.00366) of the difference between absolute zero and the triple point of water. Thus, it sets the magnitude of one degree Celsius and that of one kelvin as exactly the same. Additionally, it establishes the difference between the two scales' null points as being precisely 273.15 degrees Celsius (-273.15 °C = 0 K and 0 °C = 273.15 K).[3]

This definition fixes the magnitude of both the degree Celsius and the kelvin as precisely 1 part in 273.16 (approximately 0.00366) of the difference between absolute zero and the triple point of water. Thus, it sets the magnitude of one degree Celsius and that of one kelvin as exactly the same. Additionally, it establishes the difference between the two scales' null points as being precisely 273.15 degrees Celsius (-273.15 °C = 0 K and 0 °C = 273.15 K).[3]

Added 9/20/2012 8:01:42 AM

@kidcarbon- yes the equal each other but the question asks if they both read zero. They do not both read zero.

Added 9/20/2012 8:09:05 AM

it is false.for kelvin the freezing point it is 273k but for celsius is 0c

Added 9/21/2012 9:52:19 AM

At the freezing point of water, the temperature of the Kelvin scale reads 273 K.

0º is the freezing point of water in Celsius.