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Q: Solve the system by using elimination or elimination with multiplication. 2x + 3y = 12 and 3x + 2y = 13
A: 2x + 3y = 12 3x + 2y = 13 (2x + 3y = 12) * 3 6x + 9y = 36 (3x + 2y = 13) * 2 6x + 4y = 26 (6x + 4y = 26) - (6x + 9y = 36) -5y = -10 y = -10/-5 y = 2 2x + 3y = 12 2x + 3(2) = 12 2x + 6 = 12 2x = 12 - 6 2x = 6 x = 6/2 x = 3 Solution set: (3, 2)
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User: Solve the system by using elimination or elimination with multiplication. 2x + 3y = 12 and 3x + 2y = 13

Weegy: x=9
Expert answered|maat125|Points 111|

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Asked 6/23/2011 4:57:31 PM
Updated 1/12/2017 7:12:33 AM
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This conversation has been flagged as incorrect.
Flagged by Andrew. [1/12/2017 7:12:33 AM]
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2x + 3y = 12
3x + 2y = 13

(2x + 3y = 12) * 3
6x + 9y = 36

(3x + 2y = 13) * 2
6x + 4y = 26

(6x + 4y = 26) - (6x + 9y = 36)
-5y = -10
y = -10/-5
y = 2

2x + 3y = 12
2x + 3(2) = 12
2x + 6 = 12
2x = 12 - 6
2x = 6
x = 6/2
x = 3

Solution set: (3, 2)
Added 1/12/2017 7:12:29 AM
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