When we graph the inequality 4x - 3y?_ 0, why can’t we use (0, 0) as a test point? If we test the point (6, -5), do er obtain a false statement or a true one?the number that equation is supposed to total (6, -5)

Q: When we graph the inequality 4x - 3y?_ 0, why can’t we use (0, 0) as a test point? If we test the point (6, -5), do er obtain a false statement or a true one?the number that equation is supposed to

total (6, -5)

A: (0,0) as a test point can't be use to graph the inequality 4x - 3y because it is prefer to use a solution that is actually possible and (0,0) does makes the solution read 0 > 0 which is false. [ The number that equation is supposed to total (6,-5) is a possible solution so it is a true statement. ]

When we graph the inequality 4x - 3y?_ 0, why can’t we use (0, 0) as a test point? If we test the point (6, -5), do er obtain a false statement or a true one?the number that equation is supposed to total (6, -5)

Weegy: This is an easy mathematical problem. In order to find the slope and the Y intercept of the equation all you need to do is bring the equation in the general form, y = mx + c. It will become y = 2x - 5. [ [ In this case as we can see 2 is the slope and -5 is the y intercept. ] ] User: (8, 0), m = - 3 Weegy:
((3 / 5) * 0.6) - ((2 / 3) * 0.15) = 0.26 Thanks for asking Weegy. User: Parallel to 3x – y =7 and passes through (- 1, 0) Weegy: (3x-2) squared is 9x^2 - 12x + 4. User: 5x - 6y =19 6x + 8y = -5
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