Describe the location of the point having the following coordinates.
nonzero abscissa, negative ordinate
Quadrant II or Quadrant IV
Quadrant I or Quadrant II
Quadrant I or Quadrant IV
Quadrant

III or Quadrant IV

Your answer: Quadrant III.

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Asked 3/12/2013 7:32:03 PM

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the range is a set of what?

Weegy: The range of a set of data is the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. [ Then subtract the smallest value from the largest value in the set.
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Asked 3/12/2013 7:40:44 PM

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Which of the following represents "Twice the abscissa increased by three times the ordinate is ten"?
3x + 2y = 10
2y + 3x = 10
2x + 3y = 10

Weegy: 2y+3x User: Describe the location of the point having the following coordinates.
abscissa and ordinate have the same sign
Quadrant II or Quadrant IV
Quadrant I or Quadrant III
Quadrant I or Quadrant IV
Quadrant II or Quadrant III Weegy: Let the point be (x,y) at quadrant III, which means that both x and y are negative numbers.
Equations:
x = 3y.
I think we need one more equation, is this all the data available? User: yes thaat ... (More)

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Education|No Subcategories|Expert Answered

Asked 3/12/2013 7:26:10 PM

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Find f(-5) if f(x) = |x + 1|.
4
5
6

Weegy: The correct answer is c. That is because it is the absolute value of -5 so its 5 + 1. User: Find f(-7) if f(x) = 2x + 8.
-6
2
3
22 Weegy: The answer is a. -6 User: Find f(-3) if f(x) = x 2.
-9
-6
6
9 Weegy: It's 9. User: Find f() if f(n) = 3n.
1/3
1
3 Weegy: We can not see what you wrote inside of the brackets. Is it f(1/9), f(1/3) or f(1)? User: Find f(1/3) if f(n) = 3n.
1/3
1
3 Weegy: We can not see what you wrote ... (More)

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Updated 1 day ago|7/23/2014 12:03:22 PM

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f(-5) if f(x) = |x + 1|

f(-5) = |-5 + 1|

f(-5) = 5 - 1

f(-5) = 4

f(-5) = |-5 + 1|

f(-5) = 5 - 1

f(-5) = 4

Added 1 day ago|7/23/2014 12:01:00 PM

f(-7) if f(x) = 2x + 8

f(-7) = 2(-7) + 8

f(-7) = -14 + 8

f(-7) = -6

f(-7) = 2(-7) + 8

f(-7) = -14 + 8

f(-7) = -6

Added 1 day ago|7/23/2014 12:01:46 PM

f(1/3) if f(n) = 3n

f(1/3) = 3(1/3)

f(1/3) = 3/3

f(1/3) = 1

f(1/3) = 3(1/3)

f(1/3) = 3/3

f(1/3) = 1

Added 1 day ago|7/23/2014 12:02:31 PM

f(-11/5) if f(n) = 5n + 6

f(-11/5) = 5(-11/5) + 6

f(-11/5) = -11 + 6

f(-11/5) = -5

f(-11/5) = 5(-11/5) + 6

f(-11/5) = -11 + 6

f(-11/5) = -5

Added 1 day ago|7/23/2014 12:03:22 PM

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