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x - 2y = 3
5x + 3y = 2
The lines whose equations are shown intersect at which point?
(1, -1)
(-1, 1)
(0, 3/2)

Weegy: 31/8 and 25/8 (More)

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Updated 7/22/2012 4:47:45 PM

1 Answer/Comment

Solve the system algebraically.
2x+ y - 10 = 0
x - y - 4 = 0
What is the value of y?
1/3
2/3
14/3

Weegy: Adding both equations gives us 3x=14; Therefore x=14/3. Substituting this value to the second equation gives: (14/3)-y=4; Grouping similar terms: (14/3)-4=y; (14/3)-(12/3)=y;y Therefore is 2/3 (More)

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Updated 7/22/2012 5:37:01 PM

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2x+ y - 10 = 0 x - y - 4 = 0 What is the value of y? 1/3 2/3 14/3

To solve for y subtract the 2 equations

2x + y - 10 = 0

-x + y + 4 = 0

Answer is x + 2y - 6 = 0

get numbers on one side so x + 2y = 6

to solve for y we need it on a side by itself so we need to subtract x from both sides. When we do this we have 2y = -x + 6.

Now we divide both sides by 2 to isolate the y.

y = -x/2 + 3 This is the answer

To solve for y subtract the 2 equations

2x + y - 10 = 0

-x + y + 4 = 0

Answer is x + 2y - 6 = 0

get numbers on one side so x + 2y = 6

to solve for y we need it on a side by itself so we need to subtract x from both sides. When we do this we have 2y = -x + 6.

Now we divide both sides by 2 to isolate the y.

y = -x/2 + 3 This is the answer

Added 7/22/2012 5:37:29 PM

2x+ y - 10 = 0 x - y - 4 = 0 What is the value of y? 1/3 2/3 14/3

To solve for y subtract the 2 equations

2x + y - 10 = 0

-x + y + 4 = 0

Answer is x + 2y - 6 = 0

get numbers on one side so x + 2y = 6

to solve for y we need it on a side by itself so we need to subtract x from both sides. When we do this we have 2y = -x + 6.

Now we divide both sides by 2 to isolate the y.

y = -x/2 + 3 This is the answer

To solve for y subtract the 2 equations

2x + y - 10 = 0

-x + y + 4 = 0

Answer is x + 2y - 6 = 0

get numbers on one side so x + 2y = 6

to solve for y we need it on a side by itself so we need to subtract x from both sides. When we do this we have 2y = -x + 6.

Now we divide both sides by 2 to isolate the y.

y = -x/2 + 3 This is the answer

Added 7/22/2012 5:37:29 PM

Solve the system algebraically. Check your work.
5x + 2y = 10
3x + 2y = 6

Weegy: 5x+2y=10_3x+2y=6
Since 2y does not contain the variable to solve for, [ move it to the right-hand side of the equation by subtracting 2y from both sides.
5x=-2y+10_3x+2y=6
Divide each term in the equation by 5.
x=-(2(y-5))/(5)_3x+2y=6
Since the equation was solved for x, replace all occurrences of x in the other equations with the solution (-(2(y-5))/(5)).
x=-(2(y-5))/(5)_3(-(2(y-5))/(5))+2y=6
Multiply -2 by each term inside the ... (More)

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Updated 7/22/2012 5:29:45 PM

1 Answer/Comment

5x + 2y = 10 3x + 2y = 6 I would subtract the two equations thus you would have

5x + 2y =10

-3x - 2y = -6

The 2y would cancel out so you have 2x =4 divide both by 2 and you get x = 2.

Choose an equation and plug in a 2 for x for the first one you get 5(2) + 2y = 10

10 + 2y = 10

y = 0

Now to check try both numbers in the second equation to see if we are correct

3x +2y = 6

3(2) + 2(0) = 6

6 + 0 = 6

6 = 6

Your answer is (2,0)

5x + 2y =10

-3x - 2y = -6

The 2y would cancel out so you have 2x =4 divide both by 2 and you get x = 2.

Choose an equation and plug in a 2 for x for the first one you get 5(2) + 2y = 10

10 + 2y = 10

y = 0

Now to check try both numbers in the second equation to see if we are correct

3x +2y = 6

3(2) + 2(0) = 6

6 + 0 = 6

6 = 6

Your answer is (2,0)

Added 7/22/2012 5:29:45 PM

In your notebook, set up the following addition using a vertical format and find the sum of the given polynomials.
7b + 3, -4b + 5, and -3b + 2

Weegy: Your answer is 10
7b + 3 -4b + 5 -3b + 2
7b-4b-3b=0
3+5+2=10 (More)

Question

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Asked 7/22/2012 5:47:55 PM

0 Answers/Comments

Simplify (3x + 5) + (2x - 9) - (4x + 3).

Weegy: (3x + 5) + (2x - 9) - (4x + 3) = x - 7. [smile] (More)

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Updated 53 days ago|3/1/2014 5:52:16 AM

1 Answer/Comment

(3x+5)+(2x-9)-(4x-3)=x-7

3x +5+2x-9-4x-3=x-7

=x-7=x-7

collect the like terms.

x-x=-7+7

x=0.

3x +5+2x-9-4x-3=x-7

=x-7=x-7

collect the like terms.

x-x=-7+7

x=0.

Added 7/22/2012 6:23:14 PM

First lets plug in the point (1,-1) into the first equation x - 2y = 3

1 - 2(-1) = 3

1+ 2 = 3 This works here lets try the other equation

5x + 3y = 2

5(1) + 3 (-1) = 2

5 - 3 = 2 This works as well so this is your answer