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2x - y - 4 = 0 3x + y - 9 = 0 What is the solution set of the given system?
our answer is: x = 137/41 or 3.34
scijoe21|Points 1965|
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Asked 7/23/2012 7:23:53 PM
Updated 71 days ago|9/13/2014 2:26:09 AM
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The solution for 2x - y - 4 = 0 , 3x + y - 9 = 0 is x = 13/5, y = 6/5 .
Two equation add , we get 2x+3x = 13 , x = 13/5
Put x = 13/5 in 2x -y -4 =0
2*13/5 -y = 4
y = 26/5 - 20/5
y = 6/5 .
Added 71 days ago|9/13/2014 2:26:09 AM
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Questions asked by the same visitor
x - 2y = 3 5x + 3y = 2 The lines whose equations are shown intersect at which point? (1, -1) (-1, 1) (0, 3/2)
Weegy: 31/8 and 25/8 (More)
Question
Updated 7/22/2012 4:47:45 PM
1 Answer/Comment
To find this answer you need to try to plug in the x and y values into the equations and see which one solves both equations.
First lets plug in the point (1,-1) into the first equation x - 2y = 3
1 - 2(-1) = 3
1+ 2 = 3 This works here lets try the other equation

5x + 3y = 2
5(1) + 3 (-1) = 2
5 - 3 = 2 This works as well so this is your answer
Added 7/22/2012 4:47:47 PM
Solve the system algebraically. 2x+ y - 10 = 0 x - y - 4 = 0 What is the value of y? 1/3 2/3 14/3
Weegy: Adding both equations gives us 3x=14; Therefore x=14/3. Substituting this value to the second equation gives: (14/3)-y=4; Grouping similar terms: (14/3)-4=y; (14/3)-(12/3)=y;y Therefore is 2/3 (More)
Question
Updated 7/22/2012 5:37:01 PM
1 Answer/Comment
2x+ y - 10 = 0 x - y - 4 = 0 What is the value of y? 1/3 2/3 14/3

To solve for y subtract the 2 equations

2x + y - 10 = 0
-x + y + 4 = 0
Answer is x + 2y - 6 = 0

get numbers on one side so x + 2y = 6

to solve for y we need it on a side by itself so we need to subtract x from both sides. When we do this we have 2y = -x + 6.

Now we divide both sides by 2 to isolate the y.

y = -x/2 + 3 This is the answer
Added 7/22/2012 5:37:29 PM
2x+ y - 10 = 0 x - y - 4 = 0 What is the value of y? 1/3 2/3 14/3

To solve for y subtract the 2 equations

2x + y - 10 = 0
-x + y + 4 = 0
Answer is x + 2y - 6 = 0

get numbers on one side so x + 2y = 6

to solve for y we need it on a side by itself so we need to subtract x from both sides. When we do this we have 2y = -x + 6.

Now we divide both sides by 2 to isolate the y.

y = -x/2 + 3 This is the answer
Added 7/22/2012 5:37:29 PM
Solve the system algebraically. Check your work. 5x + 2y = 10 3x + 2y = 6
Weegy: 5x+2y=10_3x+2y=6 Since 2y does not contain the variable to solve for, [ move it to the right-hand side of the equation by subtracting 2y from both sides. 5x=-2y+10_3x+2y=6 Divide each term in the equation by 5. x=-(2(y-5))/(5)_3x+2y=6 Since the equation was solved for x, replace all occurrences of x in the other equations with the solution (-(2(y-5))/(5)). x=-(2(y-5))/(5)_3(-(2(y-5))/(5))+2y=6 Multiply -2 by each term inside the parentheses. x=((-2y+10))/(5)_3(-(2(y-5))/(5))+2y=6 Remove the parentheses around the expression -2y+10. x=(-2y+10)/(5)_3(-(2(y-5))/(5))+2y=6 Divide each term in the numerator by the denominator. x=-(2y)/(5)+(10)/(5)_3(-(2(y-5))/(5))+? Simplify each expression in -(2y)/(5)+(10)/(5). x=-(2y)/(5)+2_3(-(2(y-5))/(5))+2y=6 Multiply -2 by each term inside the parentheses. x=-(2y)/(5)+2_3(((-2y+10))/(5))+2y=6 Remove the parentheses around the expression -2y+10. x=-(2y)/(5)+2_3((-2y+10)/(5))+2y=6 Divide each term in the numerator by the denominator. x=-(2y)/(5)+2_3(-(2y)/(5)+(10)/(5))+2y? Simplify each expression in -(2y)/(5)+(10)/(5). x=-(2y)/(5)+2_3(-(2y)/(5)+2)+2y=6 Multiply 3 by each term inside the parentheses. x=-(2y)/(5)+2_(-(6y)/(5)+6)+2y=6 Reorder the polynomial -(6y)/(5)+6+2y alphabetically from left to right, starting with the highest order term. x=-(2y)/(5)+2_-(6y)/(5)+2y+6=6 Find the LCD (least common denominator) of -(6y)/(5)+2y+0. x=-(2y)/(5)+2_Least common denominator: 5 Multiply each term in the equation by 5 in order to remove all the denominators from the equation. x=-(2y)/(5)+2_4y=0 Since the equation was solved for y, replace all occurrences of y in the other equations with the solution (0). x=-(2y)/(5)+2_y=0 Since the equation was solved for y, replace all occurrences of y in the other equations with the solution (0). x=-(2(0))/(5)+2_y=0 Multiply -2*0 to get 0 in the numerator. x=(0)/(5)+2_y=0 Any expression with a factor of 0 in the numerator is equal to 0. x=0+2_y=0 Remove the 0 from the ... (More)
Question
Updated 7/22/2012 5:29:45 PM
1 Answer/Comment
5x + 2y = 10 3x + 2y = 6 I would subtract the two equations thus you would have
5x + 2y =10
-3x - 2y = -6

The 2y would cancel out so you have 2x =4 divide both by 2 and you get x = 2.

Choose an equation and plug in a 2 for x for the first one you get 5(2) + 2y = 10
10 + 2y = 10
y = 0

Now to check try both numbers in the second equation to see if we are correct
3x +2y = 6
3(2) + 2(0) = 6
6 + 0 = 6
6 = 6

Your answer is (2,0)
Added 7/22/2012 5:29:45 PM
In your notebook, set up the following addition using a vertical format and find the sum of the given polynomials. 7b + 3, -4b + 5, and -3b + 2
Weegy: Your answer is 10 7b + 3 -4b + 5 -3b + 2 7b-4b-3b=0 3+5+2=10 (More)
Question
Expert Answered
Asked 7/22/2012 5:47:55 PM
0 Answers/Comments
Simplify (3x + 5) + (2x - 9) - (4x + 3).
Weegy: (3x + 5) + (2x - 9) - (4x + 3) = x - 7. [smile] (More)
Question
Updated 267 days ago|3/1/2014 5:52:16 AM
1 Answer/Comment
(3x+5)+(2x-9)-(4x-3)=x-7

3x +5+2x-9-4x-3=x-7
=x-7=x-7
collect the like terms.
x-x=-7+7
x=0.
Added 7/22/2012 6:23:14 PM
This answer has been flagged as incorrect.
Rated good by John@evang, Rated good by John@evang, Flagged by andrewpallarca [3/1/2014 5:52:15 AM]
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