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Q: At a constant pressure and a temperature of 280 K, the gas in a cylinder has a volume of 20.0 liters. If the volume of the gas is decreased to 10.0 liters, what is the new temperature? A. 35
kilopascals. B. 105 kilopascals. C. 140 kilopascals. D. 560 kilopascals.
A: Find: V" for P'=P" Assumption: gas is ideal Using Charles's Law (Law of Volumes), since P'=P", V' / T' = V" / T" V" = V"T' / V' V" = (20.0L-10.0L)(280K) / (20.0L) V" = 140K THEREFORE its letter C.
thewolf010|Points 1150|
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Asked 8/24/2012 7:18:31 AM
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