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What is the equation of the line that passes through the point (6, 1) and is perpendicular to the line y = –3x + 2
Weegy: Let's say slope is m: m1 = (y1-y2)/(x1-x2) You have two coordinates of one line. [ Therefore, calculate its slope. m1 = (2-(-4)) / (2-4) = 6 / -2 = -3 Perpendicular slopes are negative inverses of known slopes. m2 = 1/3 Given y=mx+b, plug in the coordinate (-1,4) from your second line to find b. 4 = (-1)(1/3) + b b= 13/3 Final equation: y = 1/3 x + 13/3 ] (More)
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Asked 8/23/2011 9:08:20 AM
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What is the equation of a vertical line passing through –4 –3
Weegy: can you please rephrase your question a bit so i can find better results? User: What is the equation of the vertical line that pases through (–4, –3) Weegy: can you please rephrase your question a bit so i can find better results? User: What is the equation of the line that passes through the point (6, 1) and is perpendicular to the line y = –3x + 2 (More)
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Asked 8/23/2011 8:59:36 AM
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Multiply the quantity of 2 square root 5 minus 1 times the quantity of 3 square root 5 plus 4
Weegy: The answer is 36. Remember to use PEMDAS! (More)
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Asked 8/23/2011 9:40:11 AM
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Let f(x) = x – 3 and g(x) = x + 11. Find f(x) • g(x)
Weegy: f(x) = x – 3 and g(x) = x + 11. Find f(x) • g(x) f(x) • g(x) = (x – 3) • (x + 11) = x^2 + 11x - 3x - 33 = x^2 + 8x - 33 (More)
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Updated 47 days ago|12/25/2015 8:14:17 AM
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