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$1,500 is invested in two different accounts paying 4% and 5% interest. If a total of $67 interest is earned after one year, then how much money was invested at 4%?
We know that 1500 was invested total. [ We're trying to solve for the amount put into the 4% account. Let's say that F was put in the 4% account (F for Four percent) so the remaining money, or 1500 - F, was put into the 5% account. initial deposits 4%- F 5%- -1500 - F now, let's work it with words total interest earned = interest from 4% account + interest from 5% account total interest = (amt.
invested)(% interest) + (amount invested)(% interest) 67 = F(4%) + (1500 - F)(5% 67 = F(0.04) + (1500 - F)(0.05) 67 = F(0.04) + (1500)(0.05) - (F)(0.05) 67 = 0.04F + 75 - 0.05F 67 - 75 = 0.04F - 0.05F -8 = -0.01F -8 / -0.01 = F F = 800 So $800 was invested in the 4% account (which means that 1500 - 800 = $700 was invested in the 5% account). Check: 800 * 0.04 = 32 700 * 0.05 = 35 32 + 35 = 67 (There's our $67 total interest) ; Therefore $800 was invested @ 4% interest. ]
Expert answered|bongche|Points 1369|
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Asked 3/26/2012 8:54:10 AM
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Questions asked by the same visitor
Find the value of 7 + 3^2 (-5 + 1) ÷ 2 is it 25, 32, or -11
Weegy: 2 (More)
Question
Updated 74 days ago|8/12/2014 10:26:03 AM
1 Answer/Comment
7 + 3^2 (-5 + 1) ÷ 2

= 7 + 9 * (-4) ÷ 2;

= 7 + (-36) ÷ 2;

= 7 + (-18)

= 7 - 18;

= -11
Added 74 days ago|8/12/2014 10:26:03 AM
This answer has been confirmed as correct, not copied, and helpful.
Confirmed by andrewpallarca [8/12/2014 10:30:13 AM]
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