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given 13 bits of mask for the host portion how many host addresses are available
Question
Updated 11/7/2013 3:22:18 PM
[Deleted]
Deleted by Twinkie
When working with the host portion in subnet mask, always start from right to left. (zeros represent the host/ ones represent the network)
SOoooo
11111111.11111111.11100000.00000000

Break Down:
[11111111.11111111.111][00000.00000000] Binary Form
Network Host

there are thirteen zeros representing the host portion and 2^13 is 8,192. You have to subtract 2 leaving you with 8,190.

how many bits of mask are required to provide 30 host addressess?
Weegy: 5 bits are necessary to create up to 30 User: how many networks will be created using 255.255.0.0 given a class A IP network Weegy: 11 hosts (More)
Question
explain the reasoning behing the concept of subnet zero
Weegy: If you are familiar with the host and broadcast address for a subnet being unusable for hosts (which you should be) then you should get it because the concept is the same. [ Let me give you and example. Let's say we have 192.168.1.0/24 and we are subnetting it into /27 networks. We would have the following networks: 192.168.1.0 192.168.1.32 192.168.1.64 192.168.1.96 192.168.1.128 192.168.1.160 192.168.1.192 192.168.1.224 or a total of 8 usable subnets when using the default of allowing subnet zero. Using no ip subnet zero on the router means that we cannot use the all 0's are all 1's subnets. All 1s subnet may be referred as the broadcast subnet. Under that restriction, our available subnets would be: 192.168.1.32 192.168.1.64 192.168.1.96 192.168.1.128 192.168.1.160 192.168.1.192 ] (More)
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