Question and answer
If an object is reflected twice over parallel lines, and corresponding points of the original and final translation image are 26 centimeters apart, how far apart are the parallel lines?
Your answer has a varied range. If the object is a 2cm square, then the parallel lines are 6.5cm apart. If the object is a point, then the lines would have to be 7.5cm apart. [ Is there some designated shape to begin with? The formula below can help you solve what you are looking for. 2(object width)+4(distance of parallel lines)=30cm or 2*w + 4*d = 30 ]
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Original conversation
User: Regular heptagons cannot tessellate true or false

User: If an object is reflected twice over parallel lines, and corresponding points of the original and final translation image are 26 centimeters apart, how far apart are the parallel lines?

Weegy: Your answer has a varied range. If the object is a 2cm square, then the parallel lines are 6.5cm apart. If the object is a point, then the lines would have to be 7.5cm apart. [ Is there some designated shape to begin with? The formula below can help you solve what you are looking for. 2(object width)+4(distance of parallel lines)=30cm or 2*w + 4*d = 30 ]
jeifunk|Points 9902|

User: Complete this statement: 8 ounces is to one cup as __________ ounces is to 10 cups.





Weegy: Complete this statement: 8 ounces is to one cup as ___80_ ounces is to 10 cups.
Expert answered|Marvel2|Points 484|

User: Complete this statement: 225 students is to 9 classes as 125 students is to __________ classes.

Weegy: 225 students to 9 classes so there is 25 students in those 9 so if there 25 in each and there 125 students totally wen u divide 125/25 you get 5
Expert answered|Marvel2|Points 484|

User: what is aaa in geomentry

Weegy: n Euclidean geometry, AAA (Angle-Angle-Angle) (or just AA, [ since in Euclidean geometry the angles of a triangle add up to 180°) does not provide information regarding the size of the two triangles and hence proves only similarity and not congruence in Euclidean space. However, in spherical geometry and hyperbolic geometry (where the sum of the angles of a triangle varies with size) AAA is sufficient for congruence on a given curvature of surface. ]
Expert answered|Marvel2|Points 484|

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Asked 6/12/2013 10:55:25 AM
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